Question

Figure shows a long U-shaped wire of width l placed in a perpendicular magnetic field B. A wire of length l is slid on the U-shaped wire with a constant velocity v towards right. The resistance of all the wires is r per unit length. At t = 0, the sliding wire is close to the left edge of the U-shaped wire. Draw an equivalent circuit diagram, showing the induced emf as a battery. Calculate the current in the circuit.
Figure

Answer 1

Answer:

please tell me where is the figure it like the figure then calculate the current in a circuit

Answer 2

The current that flows in the given circuit is  $\frac{B v l}{2 r(l+v t)}$

Explanation:

The electromotive force induce is given by

e = Bvl

Net resistance, R = r × Total wire lenght

Since the length of the mobile wire is l, and the distance traveled by the mobile wire in time t is vt,

The total loop length is $2 (l + vt).$

$e=i \times 2 r(l+v t)$

$\begin{aligned}B v l &=2 r i(l+v t) \\i &=\frac{B v l}{2 r(l+v t)}\end{aligned}$

Therefore the current that flows in the circuit is given by $\frac{B v l}{2 r(l+v t)}$