Figure shows a particle starting from point A, travelling up to B with a speed u, then up to point C with a speed 2u, and finally upto A with a speed of 3u. Determine its average speed.
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Explanation:
Solution
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(Refer to Image)
90
o
120
o
150
o
D
1
=
360
90
×2πr
=
4
2πr
⇒t
1
=
4s
2πr
D
2
=
360
120
×2πr
=
3
2πr
⇒t
2
=
6s
2πr
D
3
=
360
150
×2πr
=
12
5
×2πr
⇒t
3
=
36s
10πr
Average speed=
Total Time
Total Distance
=
2πr(
4s
1
+
6s
1
+
36s
5
)
2πr(
4
1
+
3
1
+
12
5
)
=
12(9+6+5)
(3+4+5)36
s
=
20
12×3
=
10
18
=1.8s
solution
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