Figure shows a spring fixed at the bottom end of an incline of inclination 37° A small block of mass 2 kg starts slipping down the incline from a point 4.8 m away from free end of the spring. The block compresses the spring by 20 cm, stops momentarily and then rebounds through a distance of 1 m up the incline. Find (a) The friction coefficient between the plane and the block (b) spring consatnt of the spring. g= 10
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K = 822.85
K = 822.85
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From the WET we get,
mg(4.8sin37) = 0.5*k*(0.2)^2 + 0.5mv^2
57.6 = 0.02k + v^2.............(1)
From bottom to top, applying WET we get,
0.5*2*v^2 = mg(1*sin37)
or
v^2 = 12.....(2)
put (2) in eqn. (1)
we get,
0.02k = 57.6 – 12 => 45.6
k = 45.6/0.02 => 4560/2 => 2780
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