figure shows a uniform rod of length ---
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See the diagram.
Draw the free body diagrams first.
Since the rod has uniform density, m2 = 2 * m1.
Let F be the force on mass m1 by the mass m2. Let the entire rod be moving with an acceleration a.
So 32 - 20 = (m1+m2)* a
= 3 m1 * a
=> m1 * a = 4 Newtons.
For m1,
F - 20 N = m1 * a = 4
=> F = 20 + 4 = 24 Newtons.
24 N is the answer
Draw the free body diagrams first.
Since the rod has uniform density, m2 = 2 * m1.
Let F be the force on mass m1 by the mass m2. Let the entire rod be moving with an acceleration a.
So 32 - 20 = (m1+m2)* a
= 3 m1 * a
=> m1 * a = 4 Newtons.
For m1,
F - 20 N = m1 * a = 4
=> F = 20 + 4 = 24 Newtons.
24 N is the answer
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kvnmurty:
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Answered by
1
your correct answer is 24 Newton
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