Question

Figure shows plot of force magnitude vs time during the collision of a 50 g ball with wall. The initial velocity of the ball is 30 m/s perpendicular to the wall, the ball rebounds directly back with same
speed perpendicular to the wall. The maximum magnitude of the force on the ball from the wall during the collision is​

Answer 1

Answer:

1500 N

Explanation:

1)  We have, a 50 g ball moving with initial velocity 30 m/s perpendicular to wall.

We know,

By Newton's Second Law,

Rate of change of momentum  is Force.

That is,

$F=\frac{dp}{dt}$

2) Now,

F_max acts for (4-2) = 2ms

Since, direction of velocity changes when ball bounces back with same speed.

$=>\Delta p = mv-(-mv)=2mv\\ \\=2*50*10^{-3}*30=3 kgm/s$

3) $\Delta t=2ms$

That is,

$F_{mag}=\frac{\Delta p}{\Delta t} =\frac{3}{2*10^{-3}}=1500N$

Hence, Value of F_max is 1500 N.

Answer 2

Answer:

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