Question

Figure shows plot of force magnitude vs time
during the collision of a 50 g ball with wall. The
initial velocity of the ball is 30 m/s perpendicular to
the wall, the ball rebounds directly back with same
speed perpendicular to the wall. The maximum
magnitude of the force on the ball from the wall
during the collision is

Answer 1

Answer:750 N

Explanation:From the data given in question;change in momentum=2mv=2×0.05×30=3

From the graph,change in momentum is area under F-t curve=£Fdt=area of trapezium=1/2×(2ms+6ms)×Fmax= [4×10 (to the power) -3](Fmax)

Now equating both eqn we get Fmax=750 N

Answer 2

Explanation:

hope this will help you