Question

Figure shows screw gauge in which thimble has 100 divisions. Calculate
the diameter of the wire.
D) 0.435 cm
A) 0.435 mm B) 0.435 m
C) 0.0435 cm​

Answer 1

Answer:

option D

Thimble =P.S.R+(H.S.R×L.C)

P.S.R= 4mm

0.4cm

H.S.R=35 DIV

L.C. =0.001cm

Diameter of wire=0.4+(35×0.001)

=0.4+0.035

=0.435