Question

Figure shows the path travelled by a particle. It's velocity is shown at points A and B. Which of the vector in the given options best represents the avg acceleration of the particle for its motion from A to B?​

Answer 1

Answer:

option a

Explanation:

resultant always be middle of 2vectors

Answer 2

Answer

Option A best represents the average acceleration of the particle over the given path.

Explanation

Let us find the expression for the average acceleration

          $\mathbf{\bar a} = \frac{1}{T}\int_t^{t+T} \mathbf{a} dt = \frac{1}{T}\int_t^{t+T} \frac{d\mathbf{v}}{dt}dt = \frac{\mathbf{v}(t+T) - \mathbf{v}(t)}{T}.$

From the above expression, the average acceleration points in the direction of the difference of the final velocity vector and the initial velocity vector.

Let the initial velocity be along the positive x axis and the final velocity be along the negative y axis. Then, the average acceleration will lie in the third quadrant.

The vector in option A is directed in the third quadrant.

So, the vector in option A best represents the average acceleration of the particle over the given path.

#SPJ3