Question

Figure shows the position-time graph of an object in S.H.M. The correct equation representing
this motion is
​

Answer 1

Answer:

T/2=11−5=6

Amplitude =A=4

Time period = T = 6×2=12 second

So ω=

T

2π

=

12

2π

Let eq :- x=Asin(ωt+ϕ)

x=ysin(

12

2π

t+ϕ)

at t=0,x=2

putting we get :-

sin(ϕ)=1/2

So, ϕ=π/6

So, eq :- x=4sin(

12

2π

t+

6

π

)

option (d)

solution