Question

Figure shows the variation of electric field intensity E
versus distance x. What is the potential difference
between the points at x = 2 m and at x = 6 m
from O?
(N/C)
10+
2
4
6
x (m)​

Answer 1

area under E-x graph shows the potential difference

area when x=2 m,

A1=(1/2)×10×2=10 V

area when x=6 m

A2=(1/2)×10×2×2+(2×10)

=20+20=40 V

so potential difference,

40-10=30 V

option (1) is the answer