Question

figure shows the velocity time graph of an object. describe the motion of the object between 10 s to 30 s​

Answer 1

Answer:

1/3 is the answer I hope you understand now

Answer 2

Answer:

Distance covered during the 1st 10 s =areaofΔABP= 2/1 ×10×30=150m

Distance covered during the next 20 sec = area of rectangle BPQC =20×30=600m ∴

Distance covered during the last 15 sec =areaofΔCQD=2/1×15×30=225m

∴Totaldistancecovered=150m+600m+225m=97m