Question

Figure shows three capacitors
connected to a 6V power supply. What
is the charge on the 2 microfarad capacitor ​

Answer 1

Explanation:

Given Figure shows three capacitors  connected to a 6 V power supply. What  is the charge on the 2 micro farad capacitor ​

• Given the circuit diagram shows that 3 capacitors are connected to a 6 V power supply. The capacitor of capacitance 2 micro F and 3 micro F are in parallel and connected in series with 1 micro F. Therefore 1 micro F is in series with 3 micro F capacitor. Now there is a potential difference of 6 V across this series combination. Now the parallel combination of 2 and 3 micro F = 5 micro F is 1 V.
• Therefore the charge on 2 micro F capacitor = 2 μ F x 1 V = 2 μ C

Reference link will be

https://brainly.in/question/14960204

Answer 2

2μC charges flow on the 2 μF capacitor.

Explanation:

The capacitance 2μF and 3μF are in parallel combination and 2μF and 3μF are in series combination with 1μF.

The total capacitance of 2μF and 3μF capacitors is:

Cs = 2μF + 3μF = 5μF

Now, the 5μF is in series combination with 1μF capacitor.

The potential difference across the series combination is 1 volt.

Now, the charges on the 2μF is given by the formula:

Q = CV

On substituting the values, we get,

∴ Q = 2μ × 1 = 2μC