Question

Figure shows two charges of equal magnitude separated by
a distance 2a. As we move away from the charge situated at
x = 0 to the charge situated at x = 2a, which of the following
graphs shows the correct behaviour of electric field ?

Answer 1

Given:

A Figure shows two charges of equal magnitude separated by a distance 2a.

To draw:

Graph shows the correct behaviour of electric field

Calculation:

At x = 0 , Net Field intensity will be $\infty$ due to presence of charge q.

At x = a , Net field intensity will be zero due to nullification of the field intensities of both the charges.

At x = 2a , Net field intensity will be $\infty$ due to presence of charge q.

In the intermediate parts , the graph will have hyperbolic characteristics.

At x = 0 and x = 2a ,

$\boxed{E = \dfrac{kq}{{(0)}^{2}}=\infty}$

Hence the line goes to infinity at those positions.

Refer to attached graph.

Answer 2

Answer

Given:-

Two equal magnitude charges are separated by a distance of  $2a$.

We know that,

$E=\frac{kq}{r^{2} }$

• At a point $x=0$, due to the presence of charge q, the net electric field is ∞.
• Similarly, at point $x=2a$, due to the presence of charge q, the net electric field is ∞.
• At a point $x=a$, the electric field intensities of both charges are canceled out, and hence the net electric field intensity is zero.
• Thus, the graph will be hyperbolic in the intermediate parts.
• Hence, the graph given in option B is the correct answer.

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