Figure shows two conducting thin concentric shells of radii r and 3r . The outer shell carries charge q . Inner shell is neutral . Find the charge that will flow from inner shell to outer after the switch S is closed .
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When the switches are closed the potential of both the shells should be equal.
Let us assume that the charge x flows from the outer shell to inner shell
Show the charge of the outer shell becomes q-x and the charge of the inner shell is x
Since the potential of both the shells are equal
k(q-x)÷3r= kx÷r
q-x=3x
4x=q
x=q÷4
A charge of q÷4 flows from outer shell to inner shell or in other words a charge of -q÷4 flows from inner shell to outer shell.
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