Question

Figure shows velocity time graph of a particle from 0 to 10s. Areas marked and I are respectively s units and
4 units
The ratio of distance travelled to displacement undergone in this time is
A) 5.4
B)1:1
C) 4.5
D)9:1
E) 3:1​

Answer 1

Answer:

option D

Explanation:

Area under the graph gives distance and displacement. so both 5&4 are distances travelled so total distance travelled is 5+4 =9

here in the graph the velocity after sometimes comes to negative side , which means the direction is changed to opposite side and moves 4 units

so the displacement is 5 -4=1

so the answer is 9:1