Question

FiIl in the blanks. P=9000 r =6(p.a.) n (years) =3 CI=1719.14 find the amount ​

Answer 1

Answer:

3£#369£73&94+6864)(you 2

Step-by-step explanation:

I am not sure but I am a little better than the other hand if you have any questions please let us know how to do

Answer 2

Given :

• Principal = 9000

• Rate = 6% (per annum)

• Time = 3 years

To Find :

• Amount

Solution :

$\Huge\sf\implies$ ${Amount \: = 9000\: × \: \left( 1 \: + \:\ frac {6}{100}\right)³$

$\Huge\sf\implies$ ${Amount \: = 9000\: × \: \frac{106}{100}\:\frac{106}{100}\:\frac{106}{100}$

$\Huge\sf\implies$ $\boxed\color{green}{Amount\:=\:10719.144}$

$\huge\sf\color{red} {More\: Information}$

• The amount of money lent or borrowed is called the principal.

• The additional money charged for its use is called Interest

• If the interest due is added to the principal,the total money we receive or pay is called amount due at time

Important formulae :

${Amount\:= \: principal\:+\:Interest}}}$

Interest = $\frac{Principal×Rate×time}{100}$

Rate = $\frac{Interest×100}{Principal×time}$

Time = $\frac{Interest×100}{Principal×rate}$

$\begin{gathered}\Large{\boxed{\begin{array}{cc}\\the \:amount\: of\: money\: lent\: or\\ borrowed \:is \:called \:the \:principal \\\The \:additional\: money \:charged\\ for\: its \:use \:is \:called\: Interest\:\\ If \:the\: interest \:due\: is \:added\\ to \:the\: principal\:,the\: total\: money\\ we\: receive \:or\: pay \:is \:called \:amount \:due \:at \:time\end{array}}}\end{gathered}$