Question

Fiind the value of K if (2×-1) is a factor of 6ײ + K×-2

Answer 1

Answer:

K = 1

Step-by-step explanation:

(2x-1) is a factor of 6x²+kx-2

X = 1/2 is a factor of 6x²+kx-2

Putting the value of x,

6(1/2)²+k(1/2)-2 = 0

6×1/4 + k/2 -2 = 0

3/2+k/2-2 = 0

3+k/2 - 2 = 0

3+k/2 = 2

3+k = 4

K = 1

Hope it helps!!

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