Fiind the value of K if (2×-1) is a factor of 6ײ + K×-2
Answers
Answered by
0
Answer:
K = 1
Step-by-step explanation:
(2x-1) is a factor of 6x²+kx-2
X = 1/2 is a factor of 6x²+kx-2
Putting the value of x,
6(1/2)²+k(1/2)-2 = 0
6×1/4 + k/2 -2 = 0
3/2+k/2-2 = 0
3+k/2 - 2 = 0
3+k/2 = 2
3+k = 4
K = 1
Hope it helps!!
Thank you ✌️
Similar questions