Math, asked by mammu47451, 8 months ago

fill in the blank(__)×(1/2+1/3)=(3/4×1/2)+(3/4×___)​

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Answered by Anonymous
2

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5. The measures of two adjacent angles of a parallelogram are in the ratio 3:2. Find the measure of each of the angles of the parallelogram.</p><p></p><p>\begin{gathered}\begin{gathered}\begin{gathered}\\\\\sf \large \red{\underline{Given:-}}\\\\\end{gathered}\end{gathered}\end{gathered}Given:−</p><p></p><p>The measures of two adjacent angles of a parallelogram are in the ratio 3:2.</p><p></p><p>\begin{gathered}\begin{gathered}\begin{gathered}\\\\\sf \large \red{\underline{To \: Find:-}}\\\\\end{gathered}\end{gathered}\end{gathered}ToFind:−</p><p></p><p>Find the measure of each of the angles of the parallelogram.</p><p></p><p>\begin{gathered}\begin{gathered}\begin{gathered}\\\\\sf \large \red{\underline{Solution :- }}\\\\\end{gathered}\end{gathered}\end{gathered}Solution:−</p><p></p><p>\text{ \sf suppose the angles be equal to 3x and 2x} suppose the angles be equal to 3x and 2x</p><p></p><p>\boxed{ \sf \orange{ we \: have \: ardjacent \: angles \: of \: a \: parallelogram \: = 180}}wehaveardjacentanglesofaparallelogram=180</p><p></p><p>\begin{gathered}\begin{gathered}\begin{gathered}\\ \sf \underline{ \green{putting \: all \: values : }}\end{gathered}\end{gathered}\end{gathered}puttingallvalues:</p><p></p><p>\begin{gathered}\begin{gathered}\begin{gathered}\: \\ \sf \to \: 3x + 2 x = 180\: \\ \\ \sf \to \: \: \: \: \: \ : \: \: \: \: \:5x = 180 \\ \\ \: \sf \to \: \: \: \: \: \: \: \: \: \: \:x \: = \frac{180}{5} \\ \\ \sf \to \: \: \: \: \: \: \: \: \: \: \:x \: = \cancel{ \frac{180} {5} } \\ \\ \sf \to \: \: \: \: \: \: \: \: \: \: \purple{x = 36}\\\\\end{gathered}\end {gathered}\end{gathered}→3x+2x=180→ :5x=180→x=5180→x=5180→x=36</p><p></p><p>\begin{gathered}\begin{gathered}\begin{gathered}\sf \to \: 3x \\ \sf \to \: 3 \times 36 \\ \sf \to \red{108 }\\ \\ \\ \sf \to \: 2x \\ \sf \to \: 2 \times 36 \\ \sf \to \orange{72} \\\end{gathered}\end{gathered}\end{gathered}→3x→3×36→108→2x→2×36→72</p><p></p><p>

Answered by sahasubhradeep05
1

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