Question

Fill in the blank.

If x-3 is a factor p(x)=x³+12x²+142x-120___.​

Answer 1

Answer:

$x - 3 \: is \: a \: factor \: of \: p(x)$

$x - 3 = 0$

$x = 3$

$p(x) = {x}^{3} + {12x}^{2} + 142x - 120$

$p(3) = {(3)}^{3} + 12 {(3)}^{2} + 142(3) - 120$

$= 27 + 108 + 426 - 120$

$= 135 + 426 - 120$

$= 561 - 120$

$= 441$

$ans. \: 441$

Hope it helps.

Answer 2

$x - 3 = 0$

$x = 3$

$= {x}^{3} + 12 {x}^{2} + 142x - 120$

$= (3)^{3} + 12 ({3})^{2} + 142(3) - 120$

$= 27 + 12(9) + 426 - 130$

$= 27 + 108 + 426 - 130$

$= 431$