Fill in the blank: sin (3π/2 + x) sin(2π - x) [cot (3ñ/2 - x) + cot (2n + x)] =
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Answer:
sin (3π/2 + x) sin(2π - x) [cot (3ñ/2 - x) + cot (2n + x)] =1
Step-by-step explanation:
After solving you will get.
cos^2x+sin^2x
=1
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