Question

Fill in the blank:
$( {2}^{5} \div {2}^{8}) \div {2}^{ - 7}$
​

Answer 1

$\large 16$

Step-by-step explanation:

$\large( {2}^{5} \div {2}^{8}) \div {2}^{ - 7}$

$→ \large( {2}^{5 - 8}) \div {2}^{ - 7}$

$→ \large( {2}^{ - 3}) \div {2}^{ - 7}$

$→ \large{2}^{ - 3}\div {2}^{ - 7}$

$→ \large{2}^{ - 3 - ( - 7)}$

$→ \large{2}^{ - 3 + 7}$

$→ \large{2}^{ 4}$

$→\large \bf \blue{ \boxed {16}}$

Identity used -

$\large{a}^{ m}÷ {a}^{ n}= {a}^{ m-n}$

Answer 2

6 will the answer.

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