Question

fill in the blank the distence between p (x,y) and origin is​

Answer 1

We have to find out distance between points p (x,y) and origin.

We know that :-

$\tt \: Distance \: between \: two \: points \: (x_1 , y_1) \: and \: ( x_2 , y_2) : \\ \\ \tt \longrightarrow \sqrt{{ {(x_2 - x_1)}^{2} + (y_2 - y_1)}^{2} }$

Co-ordinates of origin are :- (0,0)

Now ,here :-

$\tt x_1 = x \\ \\\tt x_2 = 0 \\ \\ \\\tt y_1 = y \\ \\\tt y_2 = 0$

$\tt \longrightarrow \sqrt{{ {(0 - x)}^{2} + (0 - y)}^{2} }$

$\tt \longrightarrow \sqrt{{ {x}^{2} + y}^{2} }$

$\tt \therefore \: distance \: between \: points \: p (x,y) \: and \: origin(0,0) = \sqrt{ {x}^{2} + {y}^{2} } units$

Answer 2

☆Answer☆

Distance between points p (x,y) and origin:

• (x1,y1) and (x2,y2)

_/(x2−x1)²+ (y2−y1)² ....(1)

We have,

x1 = x and x2 = 0

y1 = y and y2 = 0

Substituting the value in (1), we get:

_/(0-x)² + (0-y)²

_/x²+y²

Hence, Distance between p(x,y) and

(0,0) is _/x²+y².

✔