Physics, asked by sebinjosaji4216, 11 months ago

Fill in the Blank : The isotope ^{12}_5 {B} having a mass 12.014 u undergoes \beta-decay to ^{12}_6 {C}  .  ^{12}_6 {C} has an excited state of the nucleus( ^{12}_6 {C} ^* )at 4.041 MeV above its ground state. If ^{12}_5 {B} decays to ^{12}_6 {C} ^* , the maximum kinetic energy of the \beta-particle in units of MeV is . . . . . . . [1 u = 931.5 MeV/c^{2}, where c is the speed of light in vacuum.]

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Answered by abhisheksingh12592
1

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