Fill in the blank: The line y =4x +5 intersects y-axis at the point —————–.
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The line y = 4x + 5 intersects y-axis
at the point ( 0 , 5 ) .
Explanation :
We know that ,
Equation of a line whose slope = m ,
and y - intercept = c is
y = mx + c ,
The point of intersection is ( 0 , c )
Now , compare y = 4x + 5 with
y = mx + c , we get
m = 4 , y - intercept ( c ) = 5
Therefore ,
Intercepting point = ( 0 , c )
= ( 0 , 5 )
Or
Substitute x = 0 in the given equation,
we get
y = 0 + 5 = 5
Therefore ,
Required point = ( x , y ) = ( 0 , 5 )
••••
at the point ( 0 , 5 ) .
Explanation :
We know that ,
Equation of a line whose slope = m ,
and y - intercept = c is
y = mx + c ,
The point of intersection is ( 0 , c )
Now , compare y = 4x + 5 with
y = mx + c , we get
m = 4 , y - intercept ( c ) = 5
Therefore ,
Intercepting point = ( 0 , c )
= ( 0 , 5 )
Or
Substitute x = 0 in the given equation,
we get
y = 0 + 5 = 5
Therefore ,
Required point = ( x , y ) = ( 0 , 5 )
••••
Answered by
2
hope this helps..........
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