Math, asked by satishsatish673, 10 months ago

Fill in the blank using the smallest digit so that 193_ 28 is divisible by 8

Answers

Answered by sanukadam721
1

Answer:

the number will be 193128

Answered by Rayleigh
1

Let the dash be filled by x.

So, the number becomes

100000 + 90000 + 3000 + 100x + 20 + 8

which has to be divisible by 8, so it must be of the form 8q where q is some integer.

100000 + 90000 + 3000 + 100x + 20 + 8 = 8q

100x + 193028 = 8q

100x + 8(241228) + 4 = 8q

100x + 4 = 8p

96x + 4x + 4 = 8p

4x + 4 = 8z

For 4x + 4 to be divisible by 8, and x to be minimum, x must be equal to 1.

Because 4 + 4 = 8 which is divisible by 8.

So, the number must must be 193128

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