Fill in the blank using the smallest digit so that 193_ 28 is divisible by 8
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Answered by
1
Answer:
the number will be 193128
Answered by
1
Let the dash be filled by x.
So, the number becomes
100000 + 90000 + 3000 + 100x + 20 + 8
which has to be divisible by 8, so it must be of the form 8q where q is some integer.
100000 + 90000 + 3000 + 100x + 20 + 8 = 8q
100x + 193028 = 8q
100x + 8(241228) + 4 = 8q
100x + 4 = 8p
96x + 4x + 4 = 8p
4x + 4 = 8z
For 4x + 4 to be divisible by 8, and x to be minimum, x must be equal to 1.
Because 4 + 4 = 8 which is divisible by 8.
So, the number must must be 193128
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