Fill in the blanks.
1.
An object that allows light to pass through it (almost) completely, is known as
object.
a
A shadow is observed, on a screen, when an
2.
object comes in,
3.
irrespective of the colour of the
object.
is a natural phenomenon that sometimes occurs on a new
4.
A
moon day.
of
When light is reflected from a plane mirror, it changes its
5.
propagation.
between it and a source of light.
Shadows formed are always
Answers
Answer:
Answer:
Angular acceleration = 10 π rad/s²
Explanation:
Given:
Initial angular velocity = 0 rad/s
Final angular velocity = 600 revolutions/minute
Time taken = 2 seconds
To Find:
Angular acceleration of the rod
Solution:
Converting angular velocity from rev/min to rad/s
We know,
600 rev/min = 2 π/60 × 600
= π/30 × 600
= 20 π rad/s
Now by the first equation of kinematics we know that,
\tt \boxed{\omega _f = \omega _i +\alpha \times t}
ω
f
=ω
i
+α×t
where \tt \omega_fω
f
= final angular velocity
\tt \omega_iω
i
= initial angular velocity
\tt \alphaα = angular acceleration
t = time taken.
Substituting the data we get,
20 π = 0 + α × 2
α = 20 π/2
α = 10 π rad/s²
Hence the angular acceleration of the rod is 10 π rad/s².
Answer:
Answer:
Answer:
Angular acceleration = 10 π rad/s²
Explanation:
Given:
Initial angular velocity = 0 rad/s
Final angular velocity = 600 revolutions/minute
Time taken = 2 seconds
To Find:
Angular acceleration of the rod
Solution:
Converting angular velocity from rev/min to rad/s
We know,
600 rev/min = 2 π/60 × 600
= π/30 × 600
= 20 π rad/s
Now by the first equation of kinematics we know that,
\tt \boxed{\omega _f = \omega _i +\alpha \times t}
ω
f
=ω
i
+α×t
where \tt \omega_fω
f
= final angular velocity
\tt \omega_iω