Fill in the blanks
1) HCF of two co-prime numbers is _________.
2) The least value should be given to * so that the number 6342*1 is divisible by 3,
is _____________.
3) The sum of the prime numbers between 60 and 75 is _____________.
4) The prime factorisation of 294 is _______________.
5) HCF of 36 & 63 is ________________.
6) The smallest number which is divisible by 2, 3, 4 and 5 is ______________.
7) The smallest number having five different prime factors is __________.
True /False
8) If a number is divisible by 14, it must be divisible by 7.
9) If ‘a’ and ‘b’ are two co-primes, then their LCM is a × b.
10) If two numbers are divisible by a number then their sum and difference are
also divisible by that number.
Answers
Solution :-
1) HCF of two co-prime numbers is 1.
2) The least value should be given to * so that the number 6342*1 is divisible by 3, is 2.
3) The sum of the prime numbers between 60 and 75 is 272.
4) The prime factorisation of 294 is 2 × 3 × 7 × 7.
5) HCF of 36 & 63 is 9.
6) The smallest number which is divisible by 2, 3, 4 and 5 is 69.
7) The smallest number having five different prime factors is 2310.
8) If a number is divisible by 14, it must be divisible by 7. The number is 140.
9) If ‘a’ and ‘b’ are two co-primes, then their LCM is a × b. The LCM of a and b where a and b are Co-primes is ab.
10) If two numbers are divisible by a number then their sum and difference are also divisible by that number.
→ Example: 16 and 20 are divisible by 4.
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The least value should be given to * so that the number 6342*1 is divisible by 3,
is _____________.
https://brainly.in/question/44416475
Answer:
Step-by-step explanation:
1
2
268
2×3×7×7
3
60
2310(2×3×5×7×11)
a = y×14=y×7×2 so it is divisible by 7
As a and b are co-prime and they have no common factor lcm of a and b is a×b
Let the two numbers be a and b
a and b both are divisible by z
a = z×q and b = z×p
a+b/z = zq+zp/z = z(q+p)/z = q+p
ab = z²pq/z = zpq