Question

fill in the blanks:
i:(a-b)²=
ii:(a²-b²)=
iii:(a+b)²=
iv:(x+a)(x+b)=​

Answer 1

Step-by-step explanation:

$\rm (\:i\:)$

$\rm \qquad (a-b)^2 =a^2+b^2-2ab$

$\rm (\:ii\:)$

$\rm \qquad a^2-b^2 = (a+b)(a-b)$

$\rm (\:iii\:)$

$\rm \qquad (a+b)^2 = a^2 +b^2 +2ab$

$\rm (\:iv\:)$

$\rm \qquad (x+a)(x+b) = x^2 +(a+b)x + ab$

Answer 2

Answer:

Step-by-step explanation: