Question

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Its very urgent

Answer 1

this is your answer

Answer 2

Hey user

Here is your answer :-

$\tan( \alpha ) = \frac{ \sin( \alpha ) }{ \cos( \alpha ) } \\ \\ \cot( \alpha) = \frac{1}{ \tan( \alpha ) }$
$\cos( \alpha ) \times \sec( \alpha ) = 1$


${ \csc}^{2} \alpha = 1 + \cot^{2} \alpha$


$\sqrt{1 + \tan^{2} \alpha } = \sec( \alpha )$


$\sqrt{ { \sin }^{2} \alpha + { \cos}^{2} \alpha } = 1$


$\sin( \alpha ) \times \csc( \alpha ) = 1$


$\tan( \alpha ) \times \cot( \alpha ) = 1$


Thank you.