fill in the blanks – phenotype ratio is found in Mendel double hybrid cross
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In mendel double hybrifmd cross ratio obtained is 9:3:3:1 is the answrr...
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The phenotypic ratio of Mendel's dihybrid cross for F1 generation was all heterozygous seeds and in F2 generation it was 9:3:3:1
Explanation:
- When two characters or traits are considered when performing a cross between any organisms, it is referred to as Dihybrid cross.
- Gregor Medel who is also called as Father of Genetics performed several cross on pea plants and gave the laws of Genetics.
- For the formulation of the Law of Independent Assortment he performed a dihybrid cross between the pea plants. And the characters he selected were the shape of the seed and the colour of the seed.
- For F1 generation, he did the cross between the homozygous dominant ( RRYY) and homozygous recessive ( rryy). The progeny of the F1 generation were all heterozygous RrYy, and all the seeds were round and yellow.
- In F2 generation, he prepared the cross between the progenies of F1 generation, that is RrYy × RrYy, then he got the phenotypic ratio of 9:3:3:1.
- In this generation independent characters were seen which was previously not seen in the parents. Hence he formulated the Law of Independent Assortment.
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