Biology, asked by solankishreya56, 9 months ago

fill in the blanks – phenotype ratio is found in Mendel double hybrid cross​

Answers

Answered by altafak999
1

Explanation:

In mendel double hybrifmd cross ratio obtained is 9:3:3:1 is the answrr...

Answered by smartbrainz
0

The phenotypic ratio of Mendel's dihybrid cross for F1 generation was all heterozygous seeds and in F2 generation it was 9:3:3:1

Explanation:

  • When two characters or traits are considered when performing a cross between any organisms, it is referred to as Dihybrid cross.
  • Gregor Medel who is also called as Father of Genetics performed several cross on pea plants and gave the laws of Genetics.
  • For the formulation of the Law of Independent Assortment he performed a dihybrid cross between the pea plants. And the characters he selected were the shape of the seed and the colour of the seed.
  • For F1 generation, he did the cross between the homozygous dominant ( RRYY) and homozygous recessive ( rryy). The progeny of the F1 generation were all heterozygous RrYy, and all the seeds were round and yellow.
  • In F2 generation, he prepared the cross between the progenies of F1 generation, that is RrYy × RrYy, then he got the phenotypic ratio of 9:3:3:1.
  • In this generation independent characters were seen which was previously not seen in the parents. Hence he formulated the Law of Independent Assortment.

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