fill in the box so that 1,0,5 are in continued proportion.
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2x−3y+4=0...(1)
x+2y−5=0...(2)
Isolate x from equation (1) and find the value of x and y.
2x−3y+4=0
or x=(3y−4)/2
xy−2 0 12 44Similarly, isolate x from equation (2) and find the values of x and y.
x+2y−5=0
or x=5−2y
x y5 03 11 2Graph:
Now,
Find the area of triangle BAD:
Area of △BAD=1/2(base×altitude)
=1/2×7×2
=7 sq.units.
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