Question

Fill out the HCF of the following pairs.
HCF (27,36)=

HCF (14,32)=

HCF (30,45)=

Answer 1

Step-by-step explanation:

1.factors of -

14=1,2,7,14

32=1,2,4,8,16,32

common factor between them are -

1*2=2

HCF of (14,32) =2

2. similarly

30=1,2,3,5,6,10,15,30

45=1,3,5,7,9,15,45

common factor between them are-

1*3*5*15=225

Answer 2

Answer:

first we find out the prime factorisation of each of these pairs.

so,

(I) 27= 3×3×3

$= 3 ^{3}$

$36 = 2 \times 2 \times 3 \times 3$

$= \: 2 ^{2} \times 3 {}^{2}$

so, HCF=

$3 {}^{2}$

(ii) 14= 2×7

32= 2×2×2×2×2

= 2^5

so, HCF= 2

(iii) 30= 2×3×5

45= 3×3×5

= 3^2 ×5

so, HCF= 3

Hope my answer is correct.