Question

Fill the blanks with solution​

Answer 1

Answer:

Hey buddy here's ur answer.

Answer 2

$\huge\underline\red{ANSWER :-}$

a) V = ( 1 cm )³ = ( 10^-2 m )³ = 10^-6 m³

b) Surface area = 2πrh + 2.πr² = 2πr ( h + r )

→ 2.22/7.2.10 ( 10.10 + 2.10 ) mm²

→ 1.5 × 10⁴ mm²

c) 18 km h^-1 = 18 × 5/18 ms^-1 = 5 ms^-1

d) Relative density of lead

= density of lead / density of water => 11.3

= distance of lead / 1 g / c.c

= distance of lead = 11.3 g/c.c or 11.3 × 10³ kg/m³

=> 1.13 × 10⁴ kg / m³