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AB = BC [Given]
∴ ∠BAC = ∠BCA [Isosceles triangle theorem]
Let ∠BAC = ∠BCA = x
(i) In ∆ABC, ∠A + ∠B + ∠C = 180° [Sum of the measures of the angles of a triangle is 180°]
∴ x + 90° + x = 180° [From (i)]
∴ 2x = 90°
∴ x = 90°/2 [From (i)]
∴ x = 45°
∴ ∠BAC = 45°
∴ AB = BC = 1/√2 × AC { opposite side of 45 ° }
= 1/√2 × √8
= 1/√2 × 2√2
∴ AB = BC = 2 unit .
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