Question

Fill the smalling missing digit such that it's divisible by 3 ...361___45

Answer 1

Step-by-step explanation:



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Ncert solutions

Grade 6

Mathematics



Chapters in NCERT Solutions - Mathematics, Class 6



Exercises in Playing With Numbers



Question 5



Q5) Write the smallest digit and the greatest digit in the blank space of each of the following

numbers so that the number formed is divisible by 3 :

(a) __ 6724 (b) 4765 __ 2

Solution

Transcript

SOLUTION:

we can find the missing number by firstly finding the sum of digits of the given numbers and then subtract it from those multiple of 3, which are greater than this sum to get the smallest and greatest digits.

i) 6+7+2+4=19

multiples of 3 greater than 19 are 21,22,27,30

therefore, 21-19=2, 24-19=5, 27-19=8, 30-19=11

smallest digit=2 greatest digit=8

ii) 4+7+6+5+2=24

24 is a multiple of 3 so smallest digit is 0 greater than 24 are 27,30,33,36

27-24=3, 30-24=6, 33-24=9 36-24=12

smallest digit=0 and greatest digit=9

Answer 2

Answer:

2 is the smallest digit

because 3+6+1+2+4+5 = 21

21 is divisible by 3

so, 2 is the smallest no.

Step-by-step explanation:

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