Question

Fill the space provided with suitable answer: $(\frac{2}{3})^{15}*(\frac{2}{3})^6*(\frac{2}{3})^{......}$

Answer 1

Answer:

$(\frac{2}{3})^{22}$

Step-by-step explanation:

Indices Rule: aⁿ x aˣ = aⁿ ⁺ ˣ

$(\frac{2}{3})^{15}*(\frac{2}{3})^6*(\frac{2}{3})$

$= (\frac{2}{3})^{15 + 6+ 1}$

$= (\frac{2}{3})^{22}$

Answer 2

HELLO DEAR,

we know:- aⁿ × aˣ = aⁿ ⁺ ˣ

So, (2/3)^15 × (2/3)^6 × (2/3)^1

=> (2/3)^(15 + 6 + 1) = (2/3)²²

I HOPE IT'S HELP YOU DEAR,

THANKS