Math, asked by samk1, 1 year ago

fill up the boxes 32°f= [ ]°c,0°c= ( )°f ,212°f ( ) °c ,100°c=( )°f ,f=9/5Celcius+( ), C=5/9[f-( )]

Answers

Answered by Anonymous
7
Heya!!!

Here is your answer...

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<> 32°F = 0°C, Please review below...
 °C = (°F - 32) * 5 / 9
= (32 - 32) * 5 / 9
= 0 * 5 / 9
= 0 / 9 = 0°C

<> 0°C = 32°F, Please Review below...
°F = 32 + °C  * 9 / 5 
=  32 + 0 * 9 / 5 
=  32 + 0 / 5
=  32 + 0 = 32°C 

<> 212°F = 100°C, Please Review Below...
°C = (°F - 32) * 5 / 9 
= 212 - 32 * 5 / 9
= 180 * 5 / 9 
= 20 * 5 = 100°C 

<> 100°C = 212°F, Please Review Below...
°F = 32 + °C * 9 / 5 
= 32 + 100 * 9 / 5 
= 32 + 20 * 9 
= 32 + 180 = 212°F 

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Hope this helps you....

Jeferson...

samk1: ok
Anonymous: Yes
samk1: wait
samk1: on tuesday the minimum temperature at Mumbai was 21.2 degrees celsius on Wednesday that minimum went down by 1.9 degree Celsius on Thursday the minimum went up by 2.8 degree Celsius find the minimum on Thursday
Anonymous: 21.2 deg - 1.9 deg + 2.8 deg
Anonymous: 21.2 deg C + 1.9 deg C
samk1: right answer kya hoga please solve step by step
samk1: if you can please please please
Anonymous: = 23.1 degree celcius is the answer
Anonymous: Keep it up bro
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