Question

Fimd the equation of the line drawn perpendicular to the x/4+y/5=1​

Answer 1

Answer:

The equation of the given line is

4

x

+

6

y

=1.

This equation can also be written as 3x+2y−12=0

⇒y=

2

−3

x+6, which is of the form y=mx+c

∴ slope of given line =−

2

3

∴ slope of line perpendicular to given line =−

{−

2

3

}

1

=

3

2

On substituting x=0 in the given equation of line,

we obtain

6

y

=1⇒y=6

∴ the given line intersect the y-axis at (0,6)

Hence, the equation of line that has slope

3

2

and passes through point (0,6) is

(y−6)=

3

2

(x−0)

⇒3y−18=2x⇒2x−3y+18=0

Thus, the required equation of the line is 2x−3y+18=0.