Math, asked by Keval965, 1 year ago

Fimd value if x-1 is factor of p(x)= k(x)^2-√2x+1

Answers

Answered by mysticd
0

Answer:

k = √2 - 1

Explanation:

p(x) = kx²-√2x+1

If (x-1) is a factor of p(x)

then p(1) = 0

=> k(1)²-√2×1 + 1 = 0

=> k -√2 + 1 = 0

=> k = √2 - 1

Therefore,.

k = √2 - 1

••••

Similar questions