Question

Fin the zero if x=½,of p(x) =2x³+x²-5x+2

Answer 1

Step-by-step explanation:

Hey mate write your question in a proper way.

Answer 2

$\large\red{\fbox{\fbox{x=\frac{1}{2} =1,-2 }}}$

$\rule{300}2$

/. ★ Solution ★ .\

$\implies\red 2x^3+x^2-5x+2=0\\ \implies 2\frac{1/2}+\frac{1/2}-5\frac{1/2}+2\\ \implies 2\frac{1}{8}+\frac{1}{4}-\frac{5}{2}+2 =0\\ \implies \frac{1}{4}-\frac{1}{4}-\frac{1}{4}+2=0\\ \implies (\frac{1/4-1/4})-(\frac{5/2+2})=0\\ \implies \frac{-5/2+2}=0\\ \implies \frac{-5+4}{2}=0\\ \implies \frac{-1}{2}=0$

we know that ,

( -1/2) never can be equal to = 0

so,

( -1/2) is not the zero of the polynomial.

$\rule{150}2$

same as ,

when we substitute x=1 in the given polynomial.

we get,

$\implies -2=0$

we also know ( -2 ) can not be equal to zero.

so,

x =1 is not the zero of the given polynomial.

$\rule{300}2$

Again,

we substitute x=2

$\implies 2x^3+x^2-5x+2=0 \\ \implies 2(2)^3+(2)^2-5(2)+2=0\\ \implies -16-4+10+2=0\\ \implies -20+12=0\\ \implies -8≠0$

again same condition is here,

Conclusion-

(1/2) , 2 , 1 are not the zeroes of the polynomial.