Question

Find:
(1/1-4i - 2/1+i) ( 3-4i/5+i)

from complex number chapter

Answer 1

Answer:

Step-by-step explanation:

→   (1/1-4i  - 2/1+i)(3-4i/5+i)

→    (1+i-2+8i)/(1-4i+i-4i²) (3-4i/5+i)

→     (9i-1/5-3i ) (3-4i/5+i)

→     (27i-3-36i²+4i)/(25-15i-3i²+i)

→    (33+31i)/(28-10i)

as i is occurring in the denominator we can rationalize

(33 + 31i)/(25 -10i +3)  

(33+31i)(28 +10i)/(28-10i)(28+10i)

{33(28+10i)+31i(28+10i)}/(28²+10²)

{924 + 330i + 868i +310i²}/884

{614 + 1198i}/884  

(307 + 599i)/442