Question

find 1-121 + 161 - 1- 31​

Answer 1

Answer:

This sequence is a arithmetic progression (I hope you are aware of it)

This sequence is a arithmetic progression (I hope you are aware of it)Here, the common difference

This sequence is a arithmetic progression (I hope you are aware of it)Here, the common differenceD = 121 - 161 = 40

This sequence is a arithmetic progression (I hope you are aware of it)Here, the common differenceD = 121 - 161 = 40First term denoted by, A = 121

This sequence is a arithmetic progression (I hope you are aware of it)Here, the common differenceD = 121 - 161 = 40First term denoted by, A = 121As the first four digit number is 1000.

This sequence is a arithmetic progression (I hope you are aware of it)Here, the common differenceD = 121 - 161 = 40First term denoted by, A = 121As the first four digit number is 1000.We have to find the number of term which is less than or equal to 1000.

This sequence is a arithmetic progression (I hope you are aware of it)Here, the common differenceD = 121 - 161 = 40First term denoted by, A = 121As the first four digit number is 1000.We have to find the number of term which is less than or equal to 1000.As, nth term is given by,

This sequence is a arithmetic progression (I hope you are aware of it)Here, the common differenceD = 121 - 161 = 40First term denoted by, A = 121As the first four digit number is 1000.We have to find the number of term which is less than or equal to 1000.As, nth term is given by,A(n) = A + (n -1)D

This sequence is a arithmetic progression (I hope you are aware of it)Here, the common differenceD = 121 - 161 = 40First term denoted by, A = 121As the first four digit number is 1000.We have to find the number of term which is less than or equal to 1000.As, nth term is given by,A(n) = A + (n -1)DOr, 1000 = 121 + (n-1)40

This sequence is a arithmetic progression (I hope you are aware of it)Here, the common differenceD = 121 - 161 = 40First term denoted by, A = 121As the first four digit number is 1000.We have to find the number of term which is less than or equal to 1000.As, nth term is given by,A(n) = A + (n -1)DOr, 1000 = 121 + (n-1)40Or, 879 = (n - 1)40

This sequence is a arithmetic progression (I hope you are aware of it)Here, the common differenceD = 121 - 161 = 40First term denoted by, A = 121As the first four digit number is 1000.We have to find the number of term which is less than or equal to 1000.As, nth term is given by,A(n) = A + (n -1)DOr, 1000 = 121 + (n-1)40Or, 879 = (n - 1)40Or, 21.975 = n - 1

This sequence is a arithmetic progression (I hope you are aware of it)Here, the common differenceD = 121 - 161 = 40First term denoted by, A = 121As the first four digit number is 1000.We have to find the number of term which is less than or equal to 1000.As, nth term is given by,A(n) = A + (n -1)DOr, 1000 = 121 + (n-1)40Or, 879 = (n - 1)40Or, 21.975 = n - 1Or, n = 22.975

This sequence is a arithmetic progression (I hope you are aware of it)Here, the common differenceD = 121 - 161 = 40First term denoted by, A = 121As the first four digit number is 1000.We have to find the number of term which is less than or equal to 1000.As, nth term is given by,A(n) = A + (n -1)DOr, 1000 = 121 + (n-1)40Or, 879 = (n - 1)40Or, 21.975 = n - 1Or, n = 22.975Thus, 22nd term is last three digit number.

This sequence is a arithmetic progression (I hope you are aware of it)Here, the common differenceD = 121 - 161 = 40First term denoted by, A = 121As the first four digit number is 1000.We have to find the number of term which is less than or equal to 1000.As, nth term is given by,A(n) = A + (n -1)DOr, 1000 = 121 + (n-1)40Or, 879 = (n - 1)40Or, 21.975 = n - 1Or, n = 22.975Thus, 22nd term is last three digit number.I hope it helps.

Answer 2

Answer:

while changing the column width, the pointer changes into double headed arrow.