Math, asked by rshab7417, 2 months ago

find (1/2)^-²+(1/8)^-²+(1/4)^-²​

Answers

Answered by pradikumar020180
0

Answer:

Answer:

Value \: of \: \left(\frac{1}{2}\right)^{-2}+\left(\frac{1}{3}\right)^{-2}+\left(\frac{1}{4}\right)^{-2}=29Valueof(

2

1

)

−2

+(

3

1

)

−2

+(

4

1

)

−2

=29

Step-by-step explanation:

Value \: of \: \left(\frac{1}{2}\right)^{-2}+\left(\frac{1}{3}\right)^{-2}+\left(\frac{1}{4}\right)^{-2}Valueof(

2

1

)

−2

+(

3

1

)

−2

+(

4

1

)

−2

=2^{2}+3^{2}+4^{2}=2

2

+3

2

+4

2

\begin{gathered} By \: Exponential Law:\\\boxed {a^{-n} = \frac{1}{a^{n}}}\end{gathered}

ByExponentialLaw:

a

−n

=

a

n

1

\begin{gathered}= 4+9+16\\=29\end{gathered}

=4+9+16

=29

Therefore,

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