Question

Find [(1/3)^-2n ÷ (1/3)^-2 × (1/3^n/2)^-2 - (1/3^-3)^n] / [(1/3^-2/3)^9/2m × (1/16^-3)^1/4] ,if m=n​

Answer 1

Step-by-step explanation:

16×2

n+2

−2×2

n+2

16×2

n+1

−4×2

n

=

16×2

2

×2

n

−2×2

2

×2

n

16×2×2

n

−4×2

2n

(asa

m+n

=a

m

−a

n

)

=

2

n

(16×2

2

−2×2

2

)

2

n

(16×2−4)

=

16×4−2×4

32−4

=

56

28

=1/2

Hope its help..