Math, asked by gowtham200121, 11 months ago

Find 1-sec8x / 1-sec4x =

Answers

Answered by Anonymous

1

Answer:

Tan8x/tan4x

Step-by-step explanation:

Here you go

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Answered by anuanku

3

Answer:

LHS=sec8x−1sec4x−1

=1−cos8xcos8x1−cos4xcos4x

=2sin2(4x)⋅cos4x2sin2(2x)⋅cos8x

=[2sin4xcos4xcos8x]⋅[sin4x2sin2(2x)]

=[sin8xcos8x]⋅[2sin2xcos2x2sin2x⋅sin2x]

=tan8xtan4x

=RHS

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