Find (1) the lateral or curved surface area of a closed cylindrical petrol storage tank that is 4.2 m in diameter and 4.5 m high. (ii) how much steel was actually used, if 1by12of the steel actually used was wasted in making the tank.
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HEY MATE HERE IS YOUR EXPLAINATION AND ANSWER
Answer
- Answer(i)Diameter of a cylindrical(closed) petrol tank=4.2 m
=Radius=
=2
=4.2
4.2
4.2 =2.1 m
=Height=4.5 m
=Curved Surface area=2πrh=2×
=7
=22
22
= ×2.1×4.5=59.4sq.m
- ×2.1×4.5=59.4sq.m(ii)Total surface area=2πr(r+h)=2×
=7
=22
22
= ×2.1×(2.1+4.5)=2×
=7
=22
22
= ×2.1×6.6=87.12 sq.m
- ×2.1×6.6=87.12 sq.mLet the amount of steel used in making the tank=x
- ×2.1×6.6=87.12 sq.mLet the amount of steel used in making the tank=xSteel wasted=
=12
=x
x
x
- x Given:Amount of steel required−Amount of steel wasted=T.S.A of the tank.
=⇒x−
=12
=x
x
x =87.12
x =87.12⇒
=12
=12x−x
12x−x
= =87.12
=87.12⇒
=12
=11x
11x
= =87.12
=⇒x=
=11
=12
12
= ×87.12=95.04sq.m
=∴95.04sq.m steel was used in actual while making such a tank.
hopefully it will help u ☺️✌️
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