Math, asked by saboorahmed941, 1 year ago

find 10 rational numbers between -3/11 and 8/11

Answers

Answered by Ishikatk
187
Multiply the rationals to expand-
-3x10/11x10  and  8x10/11x10
= -30/110 and 80/110
= -20/110, 1/110, 79/110, 42/110, 53/110, 49/110, -1/110, 72/110, 33/110, 22/110
:-)
Answered by mindfulmaisel
93

The ten rational numbers between -\frac{3}{11}\ and\ \frac{8}{11} are -\frac{3}{11},-\frac{2}{11},-\frac{1}{11}, \frac{0}{11}, \frac{1}{11}, \frac{2}{11}, \frac{3}{11}, \frac{4}{11}, \frac{5}{11}, \frac{6}{11}, \frac{7}{11}.

Since the denominators are the same value, we need not to sort the denominator such that the value of possible rational numbers are given below in the following series,  

-\frac{3}{11},-\frac{2}{11},-\frac{1}{11}, \frac{0}{11}, \frac{1}{11}, \frac{2}{11}, \frac{3}{11}, \frac{4}{11}, \frac{5}{11}, \frac{6}{11}, \frac{7}{11}

The above are the possible rational numbers between -\frac{3}{11}\ to\ \frac{8}{11}.

(\frac{0}{11}= 0 which is a valid integer such that the value is also a proper rational number). So, the series contains positive set of numbers.

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