Math, asked by vanisweeth2papate4l, 1 year ago

Find 10 rational numbers between -3/11 and 8/11

Answers

Answered by resh2
68
We know that,
-3 < -2 < -1 < 0 < 1 < 2 < 3 < 4 < 5 < 6 < 7 < 8

so, -3 /11< -2/11 < -1/11 < 0/11 < 1/11 < 2/11 < 3/11 < 4/11 < 5/11 < 6/11 < 7/11 < 8/11

Hence, -2/11, -1/11, 0/11, 1/11, 2/11, 3/11, 4/11, 5/11, 6/11 and 7/11 are the ten rational numbers lying between -3/11 and 8/11.


Answered by amitnrw
23

10 rational numbers between  -3/11 and 8/11  are -5/22 , -2/11, -3/22 , -1/11 , -1/22, 0 , 1/22 , 1/11, 2/11 , 1/2

Given:

  • Rational numbers -3/11 and 8/11

To Find:

  • 10 rational numbers between -3/11 and 8/11

Solution:

  • Rational numbers are real numbers which can be written in the form p/q where p and q are integers and q≠0
  • There exist Infinite rational numbers between any two different rational numbers.
  • create equivalent fractions :
  • By dividing or multiplying the numerator and denominator of a given fraction by the same number except zero
  • a/ b  = ak/bk      k ≠ 0

Step 1:

Multiply Numerator and denominator by 2

-3/11 = -6/22

8/11 = 16/22

Step 2:

Create rational numbers with numerator between -6 and 8 and keeping denominator 22

-5/22 , -4/22 , -3/22 , -2/22 , -1/22 , 0/22 , 1/22 , 2/22 , 3/22 , 4/22, 5/22 , 6/22 , 7/22 , 8/22 , 9/22 , 10/22 , 11/22 , 12/22 , 13/22 , 14/22 , 15/22

Step 3:

Reduce the fractions to lowest forms and choose any 10

-5/22 , -2/11, -3/22 , -1/11 , -1/22, 0 , 1/22 , 1/11, 2/11 , 1/2

Hence, 10 rational numbers between  -3/11 and 8/11  are -5/22 , -2/11, -3/22 , -1/11 , -1/22, 0 , 1/22 , 1/11, 2/11 , 1/2

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