Math, asked by nishantdas47, 10 months ago

find (104)³ using suitable identities​

Answers

Answered by Alice65
2

Hølà mate❤️

104 ^3 - 100+4^3

Using identity

a+b ^3 -. a^3 +b^3+3ab(a+b)

(100)^3 + (4)^3 +3 .100.4(100+4)

1000000+64+1200(100+4)

1000000+1264(100+4)

1001264 +126400+5056

1124864

hope it helps you

Answered by Anonymous
3

\huge\sf\underline{\pink{A}\blue{N}\red{S}\green{W}\orange{E}\purple{R}}

\sf{(104)^3}

 \sf{=(100+4) ^3}

Using\sf {=>(a+b)^3=>a^3+b^3+3×ab(a+b)}

\sf{=100 ^3 +4 ^3 +3×100×4(100+4)}

\sf=1000000+64+1200×104

\sf=1000064+124800

\sf=1124864

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