Question

find 10th term 5,15,25.....

Answer 1

hii...

here , first term ( a ) = 5 and common difference ( d ) = 10

=> Tn = a + ( n-1 ) d

=> T10 = 5 + ( 10 - 1 ) 10

=> T10 = 5 + 9×10 = 95 answer.

__________

hope this helps !

Answer 2

Answer:

$\huge{\boxed{\boxed{\sf{a10=95}}}}$

Step-by-step explanation:

$\huge{\boxed{\boxed{\underline{\sf{SOLUTION-}}}}}$

□a=5

□d=a2-a1

=15-5=10

To find

○a10=?

$a10 = a + 9d \\ = )5 + 9 \times 10 \\ = )5 + 90 \\ = )95$

>>Another method:

$an = a + (n - 1)d \\ a10 = 5 + (10 - 1) \times 10\\ = )5 + 9 \times 10 \\ = )5 + 90 \\ = )95$

$\huge{\boxed{\boxed{\sf{a10=95}}}}$